The following table shows the percentage (%) distribution of number of members…

2023

The following table shows the percentage (%) distribution of number of members (both male and female) and number of male members in five health clubs A–E in the year 2022. Total number of members (both males and females) in health club C is 1764 and number of male members in health club E is 576. Based on the data in the table, answer the questions that follow

Health Club-Wise Distribution of Members

Health Club

Members (Male & Female)

Male

A

21%

21%

B

33%

32%

C

14%

19%

D

20%

20%

E

12%

8%

What is the average number of female members in health clubs A, B and C?

Answer: A. 1128ConceptWhen a category count and its percentage share are known, the grand total equals count ÷ percentage (in decimal form). A subgroup count is found by…

  1. A.

    1128

  2. B.

    1144

  3. C.

    1136

  4. D.

    1096

Show answer & explanation

Correct answer: A

Concept

When a category count and its percentage share are known, the grand total equals count ÷ percentage (in decimal form). A subgroup count is found by applying its percentage to the relevant grand total, and female members equal total members minus male members.

Application

  1. Club C has 1,764 total members, which is 14% of all members. Therefore, the grand total of members is 1,764 ÷ 0.14 = 12,600.

  2. Club E has 576 male members, which is 8% of all male members. Therefore, the grand total of male members is 576 ÷ 0.08 = 7,200.

  3. For club A: total members = 21% of 12,600 = 2,646; male members = 21% of 7,200 = 1,512; female members = 2,646 − 1,512 = 1,134.

  4. For club B: total members = 33% of 12,600 = 4,158; male members = 32% of 7,200 = 2,304; female members = 4,158 − 2,304 = 1,854.

  5. For club C: total members = 1,764; male members = 19% of 7,200 = 1,368; female members = 1,764 − 1,368 = 396.

  6. The average number of female members is (1,134 + 1,854 + 396) ÷ 3 = 3,384 ÷ 3 = 1,128.

Cross-check

Multiplying the average by the three clubs gives 1,128 × 3 = 3,384, which equals 1,134 + 1,854 + 396. Hence, the required average is 1,128.

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