The following table shows the number of employees working in four different…
2023
The following table shows the number of employees working in four different colleges A-D, along with the numbers of male, female, teaching, and non-teaching employees in a given year. Missing values are marked with a dash and may be calculated when required.
College-wise details of employees
College | Employees | Male employees | Female employees | Teaching males | Non-teaching males | Teaching females | Non-teaching females |
|---|---|---|---|---|---|---|---|
A | 756 | 526 | - | 325 | - | - | - |
B | - | - | - | 215 | - | 254 | - |
C | - | 159 | - | - | - | - | - |
D | 224 | 142 | 82 | - | - | - | - |
In College A, if the number of non-teaching females is 2 more than half the number of teaching females, then what is the difference between non-teaching males and non-teaching females?
Answer: B. 123 — ConceptWhen a total is divided into complementary categories, subtract the known category to obtain the missing category or part. If two unknown parts are…
- A.
130
- B.
123
- C.
120
- D.
118
Show answer & explanation
Correct answer: B
Concept
When a total is divided into complementary categories, subtract the known category to obtain the missing category or part.
If two unknown parts are related, represent them with variables and solve the resulting equations.
Application
Female employees in College A = 756 − 526 = 230.
Non-teaching males = 526 − 325 = 201.
Let T be teaching females and N be non-teaching females. Then T + N = 230 and N = T/2 + 2.
Substitute the relation: T + T/2 + 2 = 230, so 3T/2 = 228 and T = 152.
Therefore N = 152/2 + 2 = 78.
Required difference = 201 − 78 = 123.
Cross-check
The female split is 152 + 78 = 230.
The stated relation gives 152/2 + 2 = 78.
Both independent checks hold, so the required difference is 123.