The following table shows the marks scored by six students (A–F) in six…
2025
The following table shows the marks scored by six students (A–F) in six different subjects S1 to S6 having 160, 160, 120, 120, 200 and 240 as maximum marks respectively. Based on the data in the table, answer the questions that follow.
Students | S1 (Out of 160) | S2 (Out of 160) | S3 (Out of 120) | S4 (Out of 120) | S5 (Out of 200) | S6 (Out of 240) |
|---|---|---|---|---|---|---|
A | 76 | 84 | 66 | 56 | 154 | 144 |
B | 120 | 100 | 84 | 76 | 136 | 132 |
C | 128 | 72 | 64 | 70 | 144 | 160 |
D | 84 | 130 | 96 | 84 | 104 | 168 |
E | 64 | 128 | 90 | 92 | 174 | 70 |
F | 70 | 96 | 60 | 56 | 164 | 96 |
The marks scored by student B and student C together in subject S1 is ____ % more than the marks scored by student A and student D together in the same subject.
- A.
55
- B.
45
- C.
120
- D.
155
Attempted by 16 students.
Show answer & explanation
Correct answer: A
First, find the marks scored by students B and C in subject S1 from the table.
Student B scored 120 and Student C scored 128, so their combined total is 120 + 128 = 248.
Next, find the marks scored by students A and D in subject S1.
Student A scored 76 and Student D scored 84, so their combined total is 76 + 84 = 160.
Now, calculate the percentage increase using the formula: ((Difference / Original Value) * 100).
The difference is 248 - 160 = 88. The percentage increase is (88 / 160) * 100 = 55%.