The following table shows the marks obtained by six students A-F in six…
2026
The following table shows the marks obtained by six students A-F in six different subjects S1 to S6 having 160, 160, 120, 120, 200 and 240 as maximum marks, respectively. Based on the data in the table, answer the questions that follow:
Students-wise Details of Marks obtained
Student | S1 (Out of 160) | S2 (Out of 160) | S3 (Out of 120) | S4 (Out of 120) | S5 (Out of 200) | S6 (Out of 240) |
A | 80 | 84 | 66 | 56 | 154 | 150 |
B | 120 | 100 | 84 | 76 | 136 | 132 |
C | 128 | 72 | 64 | 70 | 144 | 160 |
D | 84 | 130 | 96 | 84 | 104 | 168 |
E | 64 | 128 | 90 | 92 | 174 | 70 |
F | 70 | 96 | 60 | 56 | 164 | 100 |
What is the ratio of the total marks scored by student B in all the subjects to the total marks scored by student E in all subjects?
- A.
26 : 27
- B.
108 : 103
- C.
16 : 17
- D.
46 : 47
Attempted by 4 students.
Show answer & explanation
Correct answer: B
To find the ratio, we first calculate the total marks scored by each student across all six subjects.
For Student B, summing the scores: 120 + 100 + 84 + 76 + 136 + 132 = 648.
For Student E, summing the scores: 64 + 128 + 90 + 92 + 174 + 70 = 618.
The required ratio is therefore 648: 618.
To simplify this fraction, we divide both terms by their greatest common divisor.
Both numbers are divisible by 6: 648 ÷ 6 = 108 and 618 ÷ 6 = 103.
Thus, the simplified ratio is 108: 103.
This matches Option B.