Match List I with List - II. List - I (Queries) List - II (Probability) (A) A…
2024
Match List I with List - II.
List - I (Queries) | List - II (Probability) |
(A) A bag contains 6 white and 4 red balls. Two balls are drawn at random. What is the chance, they will be the same colour? | (I) 3/68 |
(B) In a pack of 52 cards, one card is drawn at random, what is the probability that it is either a king or a queen? | (II) 14/68 |
(C) A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, find the probability of 1 red and 2 white balls? | (III) 2/13 |
(D) A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random. Find the probability of 2 blue and 1 red balls? | (IV) 7/15 |
Choose the correct answer from the options given below:
- A.
(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
- B.
(A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- C.
(A)-(IV), (B)-(III), (C)-(II), (D)-(I)
- D.
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Attempted by 34 students.
Show answer & explanation
Correct answer: D
Calculate each item and match it with List II:
(A) Same colour from 6 white and 4 red balls, drawing 2:
Favourable ways = C(6,2) + C(4,2) = 15 + 6 = 21.
Total ways = C(10,2) = 45.
Probability = 21/45 = 7/15, so (A) -> (IV).
(B) One card from a 52-card pack is either a king or a queen:
Favourable cards = 4 kings + 4 queens = 8.
Probability = 8/52 = 2/13, so (B) -> (III).
(C) From 6 red, 4 white and 8 blue balls, drawing 1 red and 2 white:
Favourable ways = C(6,1) x C(4,2) = 6 x 6 = 36.
Total ways = C(18,3) = 816.
Probability = 36/816 = 3/68, so (C) -> (I).
(D) From 6 red, 4 white and 8 blue balls, drawing 2 blue and 1 red:
Favourable ways = C(8,2) x C(6,1) = 28 x 6 = 168.
Total ways = C(18,3) = 816.
Probability = 168/816 = 7/34 = 14/68, so (D) -> (II).
Therefore, the correct matching is (A)-(IV), (B)-(III), (C)-(I), (D)-(II), which is option D.