Direction : Series I: 8, 9, 15, 25, 42, 68, 105 Series II: 60, 180, 450, 900,…

2020

Direction : Series I: 8, 9, 15, 25, 42, 68, 105
Series II: 60, 180, 450, 900, 1350, 1380, 675
Wrong term of series I is the nearest square of which of the given term?

  1. A.

    5

  2. B.

    4

  3. C.

    8

  4. D.

    7

  5. E.

    3

Attempted by 4 students.

Show answer & explanation

Correct answer: E

Concept

In a 'wrong-term' number series, every term is generated from the previous term by one fixed rule. Find the rule that fits the majority of the gaps; the single term that does not obey it is the wrong term. Here each step adds a value of the form n2 + 1, where n = 1, 2, 3, … counts the steps.

Application

Apply term(next) = term(prev) + (n2 + 1) to Series I starting from 8:

  1. 8 + (12 + 1) = 8 + 2 = 10

  2. 10 + (22 + 1) = 10 + 5 = 15

  3. 15 + (32 + 1) = 15 + 10 = 25

  4. 25 + (42 + 1) = 25 + 17 = 42

  5. 42 + (52 + 1) = 42 + 26 = 68

  6. 68 + (62 + 1) = 68 + 37 = 105

The rule rebuilds the series as 8, 10, 15, 25, 42, 68, 105. Comparing with the given 8, 9, 15, 25, 42, 68, 105, only the second term differs: it is given as 9 but should be 10. So the wrong term is 9.

Cross-check

The question asks: the wrong term is the perfect square of which given option value? The wrong term is 9, and 9 = 32. So the required number is 3. As a contrast, 42 = 16, 52 = 25, 72 = 49, 82 = 64 — none of these equals 9.

Therefore the answer is 3.

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