If the second half of the English alphabets is written in the reverse order,…

Concept: When a stated portion of the alphabet is reversed, first rebuild the complete 26-letter sequence under the new arrangement. Positions are then read as "Nth from the left/right end" by counting inclusive from that end, and "Nth to the left of a reference letter" means N steps further toward the start of the SAME rebuilt sequence from that reference letter’s position.

Application:

1. Write the standard alphabet with position numbers: A(1), B(2), ... M(13), N(14), O(15), ... Z(26).

2. Split it into two halves: first half A–M (positions 1–13) and second half N–Z (positions 14–26).

3. Reverse only the second half. N, O, P, Q, R, S, T, U, V, W, X, Y, Z becomes Z, Y, X, W, V, U, T, S, R, Q, P, O, N, and this reversed block is placed back into positions 14–26; the first half (A–M) stays unchanged in positions 1–13.

4. The new sequence from position 14 to 26 is therefore: Z(14), Y(15), X(16), W(17), V(18), U(19), T(20), S(21), R(22), Q(23), P(24), O(25), N(26).

5. Locate the 5th letter from the right end: counting inward from position 26, N is 1st, O is 2nd, P is 3rd, Q is 4th, and R is 5th — so this reference letter is R, at position 22.

6. Locate the 7th letter to the left of R (position 22): moving 7 positions toward the start of the sequence gives position 22 − 7 = 15.

7. Reading off position 15 in the rebuilt sequence gives the letter Y.

Cross-check: Step left one position at a time from R (position 22): S is at 21, T at 20, U at 19, V at 18, W at 17, X at 16, and Y at 15 — exactly seven single steps from R, landing on Y. This independently confirms the position-15 result above.

The 7th letter to the left of the 5th letter from the right end is Y.