Find the missing term (?) in the alphanumeric series: J2Z, K4X, I7V, ?, H16R,…

Concept

An alphanumeric series can be decomposed into independent position-wise sequences.

Track each letter or number across the terms and extend its consistent recurrence into the blank.

Application

1. Middle numbers: 2, 4, 7, ?, 16, 22. Their successive increases are +2, +3, +4, +5, and +6, so the missing number is 7 + 4 = 11.

2. Final letters: Z, X, V, ?, R, P correspond to 26, 24, 22, ?, 18, 16. The alphabet position falls by 2 each time, so the missing final letter is position 20, namely T.

3. First letters form two interleaved sequences. Odd positions are J, I, H (10, 9, 8), decreasing by 1; even positions are K, ?, M (11, ?, 13), increasing by 1. Therefore the missing first letter is position 12, namely L.

Cross-check

The odd-position first letters J→I→H continue by −1, while the even-position first letters K→L→M continue by +1. From the inserted term onward, the numbers 11→16→22 increase by +5 and +6, and the final letters T→R→P continue by −2. All three recurrences remain consistent.

Therefore, the missing term is L11T.