Direction: Read the following information carefully and answer the questions…

Concept

In a floor- or level-based vertical arrangement puzzle, every clue about “above / below / adjacent / gap” translates directly into a numeric constraint on position numbers (say position 1 = topmost, position 6 = bottommost). Solve by first fixing the boxes anchored by the most restrictive fixed-gap clues, then use the remaining relative clues, one at a time, to eliminate every other placement until each box and colour is pinned to a single unique position.

Application

1. Number the six positions 1 (top) to 6 (bottom). “L is four boxes above the Pink box” allows only two placements four positions apart in a six-box stack: (L = 1, Pink = 5) or (L = 2, Pink = 6).

2. Testing (L = 2, Pink = 6): Red must sit adjacent to Pink, so Red = 5, and since V sits just above the Red box, V = 4 — leaving J, N, Q and R for positions 1, 3, 5 and 6. The White-box-to-N three-position gap only has room at N = 3 or N = 5 here: N = 3 fails immediately, since it would need White at position 0 or 6, and position 6 already holds Pink. So N = 5, which forces White = 2 (box L's position). The equal-count clue (as many boxes above Green as below J) then balances only at Green = 1 and J = 6 — J = 1 pushes Green to position 6, which is already Pink, and J = 3 pushes Green to position 4 (box V), which the “neither V nor R holds Green or White” clue rules out. With Blue required below Yellow, the remaining two colours split as Yellow = 3 and Blue = 4 (box V), leaving Q and R for positions 1 and 3; since Q cannot hold Yellow, Q = 1 (Green) and R = 3 (Yellow). But Q = 1 sits above L = 2, directly contradicting “Q is placed below L.” This entire branch is therefore rejected.

3. So (L = 1, Pink = 5) is correct. Red must be adjacent to Pink, so Red = 4 or Red = 6. The clue that the White box and box N sit exactly three positions apart, with neither at the top or bottom, has only one valid pair of positions across a six-slot stack — (2, 5), since the other three-apart pairs, (1, 4) and (3, 6), each include an endpoint. If Red = 6, then V (just above Red) occupies position 5 — but position 5 must be able to hold either White or N under that gap clue, and a box already fixed there (V, holding Pink) can be neither. So this branch is impossible: Red = 4 and V = 3.

4. With positions 2 and 5 the only valid (White, N) pair, and position 5 already fixed as Pink (since Red = 4 and Pink = 5 are now both settled, and position 5 is not occupied by any already-placed box), box N itself must be the one to occupy position 5, holding the Pink colour, while White takes position 2.

5. The equal-count clue — as many boxes above the Green box as below box J — only balances (0 = 0) when Green sits at position 1 and J sits at position 6; any other split runs out of positions or forces V into the Green colour, which is barred by “Neither V nor R contains Green or White.”

6. That leaves Blue and Yellow for positions 3 and 6. Since Blue must sit below Yellow, Blue = 6 (box J) and Yellow = 3 (box V). The two boxes left, Q and R, take positions 2 and 4; because R cannot hold White (barred by the same Green/White restriction), R takes the Red-coloured position 4 and Q takes the White-coloured position 2.

Cross-check

Checking every clue against this arrangement: the four-box Pink gap, the three-box White–N gap (with neither at the ends), the V-just-above-Red placement, the equal above/below count for Green and J, the Red–Pink adjacency, Q below L, V and R avoiding Green/White, and Blue below Yellow — all eight hold simultaneously, and the alternate starting branch was already ruled out. The arrangement is unique.

The completed stack, top to bottom, is: L-Green, Q-White, V-Yellow, R-Red, N-Pink, J-Blue. Comparing this against the options, box N actually holds Pink, not Yellow — so “N-Yellow” is the combination that does not match the arrangement, making it the incorrect one.