A, B, C, D, E, F and G are sitting around a circle, facing the centre. B is…

2025

A, B, C, D, E, F and G are sitting around a circle, facing the centre. B is second to the right of C. C is third to the right of D. F is third to the right of G. G is not an immediate neighbour of B. A is third to the left of E, then who is second to the right of F?

  1. A.

    E

  2. B.

    G

  3. C.

    D

  4. D.

    A

Attempted by 3 students.

Show answer & explanation

Correct answer: D

In a circular seating puzzle where everyone faces the centre, every 'right' and 'left' clue moves along one fixed rotational direction around the circle. Numbering the seven seats 0 to 6 in that direction, an 'nth to the right' clue adds n to the reference person's seat number, and an 'nth to the left' clue subtracts n, both taken modulo 7 (so seat 6 is followed by seat 0).

  1. Fix D at seat 0 as the starting reference.

  2. C is third to the right of D, so C sits at seat 0 + 3 = 3.

  3. B is second to the right of C, so B sits at seat 3 + 2 = 5.

  4. The four remaining seats, 1, 2, 4 and 6, must hold A, E, F and G, linked by two more clues: F is third to the right of G, and A is third to the left of E.

  5. G must sit at seat 6 or seat 1: placing G at seat 2 would force F to seat 5 (already B) and placing G at seat 4 would force F to seat 0 (already D), both impossible, so only seats 6 and 1 remain to test.

  6. Placing G at seat 6 forces F to seat 6 + 3 = 2 (wrapping past seat 6). The two seats left, 1 and 4, would then need to hold A and E with E three seats to A's right; but that leaves G at seat 6, right next to B at seat 5, which breaks the rule that G is not an immediate neighbour of B, so this placement is rejected.

  7. Placing G at seat 1 forces F to seat 1 + 3 = 4. The two seats left, 2 and 6, then hold A and E: taking A at seat 6 gives E at seat 6 + 3 = 2 (wrapping past seat 6), which fits both remaining seats.

  8. Checking neighbours confirms this placement: B is at seat 5, so its immediate neighbours are seats 4 and 6; G is at seat 1, which is neither, so the non-adjacency rule holds and this is the valid seating.

Seat

Person

0

D

1

G

2

E

3

C

4

F

5

B

6

A

  • B second to the right of C: seat 3 + 2 = 5, which is B — holds.

  • C third to the right of D: seat 0 + 3 = 3, which is C — holds.

  • F third to the right of G: seat 1 + 3 = 4, which is F — holds.

  • G not an immediate neighbour of B: B's neighbours are seats 4 and 6, and G is at seat 1 — holds.

  • A third to the left of E: seat 2 − 3 wraps to seat 6, which is A — holds.

F sits at seat 4, so the seat two places to its right is seat 4 + 2 = 6, which is occupied by A. The seat second to the right of F therefore belongs to A.

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