Directions: Study the following information carefully and answer the questions…
2023
Directions: Study the following information carefully and answer the questions given below:
Eight persons work in two different departments i.e., Research and Agriculture and all of them get different marks in the Research and Agriculture sessions organized by organization. Each of them has different years of experience (in whole number) in their departments. They have qualification in either HR or diploma. No one has more experience than 11 years. Equal number of persons work in both departments. A and D have same qualification. B gets twice marks as the experience of F and doesn’t qualification in HR. F has twice experience than E who has more experience than A. F did Diploma same as C. A’s marks is two more than B’s marks but not multiple of 7. C and D have different qualification. The one who gets marks in multiple of 8 works in agriculture department. G’s experience is equivalent to smallest two digits prime number. F have 4 marks less than E. G’s experience and C’s Mark are not equal. G gets the marks which is 3/2 of the marks get by A. C’s experience is five times of A’s experience. The marks get by D is twice of C’s experience. A and D work in the same department but not as B. A gets marks which is twice of C marks. C and F work in same department but not as A’s department. A has even number of experiences. B has more experience than H but less than D and all have prime number experience. E and H work in same department. E, G and H have same qualification but different than B. H marks is 9 more than E and just less than D.
What is the sum of the experience of A, C, F and H?
- A.
33 years
- B.
28 years
- C.
23 years
- D.
39 years
- E.
26 years
Attempted by 1 students.
Show answer & explanation
Correct answer: C
Concept
In a constraint-based reasoning puzzle, fix the fully-determined clues first — values pinned by an external fact or by a unique multiplier — and then propagate them through the relational clues. The bounding conditions (whole-number years, a stated maximum, all values distinct, and any prime restriction) are what eliminate every remaining possibility.
Application
The question asks only for the years of experience of A, C, F and H, so we solve just the experience sub-system, ignoring the marks/department/qualification clues.
G's experience equals the smallest two-digit prime number, so G = 11.
C is five times A's experience and A is an even number; since no value may exceed 11, the only even A with 5A ≤ 11 is A = 2, giving C = 10.
E has more experience than A (so E > 2) and F is twice E with F ≤ 11, so E can be 3, 4 or 5; but C is already 10, so F cannot be 10, ruling out E = 5.
All eight values are distinct. If E = 3 then F = 6, leaving only the two primes 5 and 7 for the three people B, D and H — who each need a distinct prime year with H < B < D. Two primes cannot fill three slots, so E = 3 is impossible. Hence E = 4 and F = 8.
The unused primes (excluding 2 and 11) are 3, 5 and 7; the order H < B < D forces H = 3 (with B = 5 and D = 7).
Therefore the required sum is A + C + F + H = 2 + 10 + 8 + 3 = 23 years.
Cross-check
Person | Experience (years) |
|---|---|
A | 2 |
B | 5 |
C | 10 |
D | 7 |
E | 4 |
F | 8 |
G | 11 |
H | 3 |
The eight experience values 2, 4, 5, 8, 10, 11, 3 and 7 (for A, E, B, F, C, G, H, D) are all distinct whole numbers at most 11. The experiences of B, H and D — namely 5, 3 and 7 — are all prime and satisfy 3 < 5 < 7, and both G = 11 and C = 5A hold. The set is fully consistent.