The length of train A is x+10 meters and length of train B is x+20 meters…
2025
The length of train A is x+10 meters and length of train B is x+20 meters respectively. Both trains cross each other is 11/2 seconds and speed of train A is 90 km/hr. The speed of train B is 40% more than that of train A, then find the time taken by the train B to cross a 110 meters long platform (in seconds)?
- A.
10
- B.
12
- C.
8
- D.
6
- E.
16
Attempted by 3 students.
Show answer & explanation
Correct answer: C
Train A speed = 90 km/hr = 25 m/s. Train B speed is 40% more, so it is 126 km/hr = 35 m/s.
They cross each other in 5.5 s with relative speed 60 m/s, so combined length = 60 x 5.5 = 330 m.
Lengths are x + 10 and x + 20, so 2x + 30 = 330 and x = 150. Train B length = 170 m.
Time for B to cross a 110 m platform = (170 + 110)/35 = 8 s.