A sum of ₹ 8000 on simple interest becomes ₹ 9600 in 5 years at a certain rate…

2025

A sum of ₹ 8000 on simple interest becomes ₹ 9600 in 5 years at a certain rate of interest. If the rate of interest becomes double of itself, then the same sum in 6 years will become:-

  1. A.

    ₹ 11640

  2. B.

    ₹ 12680

  3. C.

    ₹ 11840

  4. D.

    ₹ 14240

Attempted by 3 students.

Show answer & explanation

Correct answer: C

Simple interest is calculated as SI = (P × R × T) / 100, and the amount is Amount = P + SI. When only the amount after a certain time is given, the unknown rate R can first be found from the known data, and then re-applied for the new conditions asked in the question.

  1. The original data gives SI = ₹9600 − ₹8000 = ₹1600 on a principal of ₹8000 over 5 years. Using SI = (P × R × T)/100: R = (1600 × 100) / (8000 × 5) = 4% per annum.

  2. The question states that the rate becomes double of itself, so the new rate is R' = 2 × 4% = 8% per annum.

  3. The new interest is worked out on the same ₹8000 principal for the new 6-year period: SI' = (8000 × 8 × 6) / 100 = ₹3840.

  4. The new amount is Principal + New interest = ₹8000 + ₹3840 = ₹11840.

As a check, the original rate of 4% gives an annual interest of ₹320, so ₹320 × 5 = ₹1600, which correctly reproduces the given amount of ₹9600 after 5 years — confirming R = 4% is right before it is doubled and reapplied.

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