On selling a tea-set at 5% loss and a lemon set at 15% gain, a crockery seller…

2016

On selling a tea-set at 5% loss and a lemon set at 15% gain, a crockery seller gains ₹7. If he sells the tea-set at 5% gain and the lemon set at 10% gain, he gains ₹13. The cost price of the lemon set is:

  1. A.

    ₹80

  2. B.

    ₹100

  3. C.

    ₹120

  4. D.

    ₹115

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Show answer & explanation

Correct answer: A

Concept. When an item is sold at a percentage profit or loss, the rupee gain or loss equals that fraction of its cost price. If two items with cost prices x and y are sold together, the net rupee gain is the algebraic sum of the individual gains/losses: (rate on x)·x + (rate on y)·y, where a loss carries a negative rate. Two such selling scenarios give two linear equations in x and y, which can be solved simultaneously.

Application. Let the cost price of the tea-set be x and of the lemon set be y.

  1. Scenario 1 — tea-set at 5% loss, lemon set at 15% gain, net gain ₹7: −0.05x + 0.15y = 7.

  2. Scenario 2 — tea-set at 5% gain, lemon set at 10% gain, net gain ₹13: 0.05x + 0.10y = 13.

  3. Add the two equations so the x-terms cancel: (−0.05x + 0.05x) + (0.15y + 0.10y) = 7 + 13, giving 0.25y = 20.

  4. Solve for y: y = 20 ÷ 0.25 = 80.

Cross-check. Substitute y = 80 into Scenario 2: 0.05x + 0.10(80) = 13 → 0.05x + 8 = 13 → x = 100. Check Scenario 1: −0.05(100) + 0.15(80) = −5 + 12 = 7 ✓. Both scenarios hold, so the lemon set costs ₹80.

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