Two vessels A and B contain mixtures of ethanol and water, having these in the…
2025
Two vessels A and B contain mixtures of ethanol and water, having these in the ratio 5:2 and 7:6, respectively. To obtain a new mixture having ethanol and water in the ratio 8:5, in what ratio should the mixtures from vessels A and B be mixed?
- A.
7:4
- B.
7:6
- C.
7:9
- D.
6:7
- E.
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Correct answer: C
To solve this problem, we can use the method of allegation, which is ideal for finding the ratio in which two mixtures must be combined.
Step-by-Step Analysis
Analyze the Ratios:
Vessel A: Ethanol to Water = 5:2. The fraction of ethanol is 5 / (5 + 2) = 5/7.
Vessel B: Ethanol to Water = 7:6. The fraction of ethanol is 7 / (7 + 6) = 7/13.
Target Mixture: Ethanol to Water = 8:5. The fraction of ethanol is 8 / (8 + 5) = 8/13.
Apply Allegation:
We want to find the ratio of Vessel A to Vessel B. Let's look at the difference between the ethanol fractions:
Difference between Vessel B and Target: |7/13 - 8/13| = 1/13
Difference between Vessel A and Target: |5/7 - 8/13|
To calculate |5/7 - 8/13|, find a common denominator (7 * 13 = 91):
|65/91 - 56/91| = 9/91
Find the Ratio:
The ratio of Vessel A to Vessel B is the ratio of these differences:
Ratio = (1/13) : (9/91)
Multiply both sides by 91:
(1/13 * 91) : (9/91 * 91) = 7 : 9
The correct ratio in which the mixtures from vessels A and B should be mixed is 7:9, which corresponds to Option 3.