Read the following data carefully and answer the questions given below. The…
2024
Read the following data carefully and answer the questions given below.
The data shows the three different people (A, B & C) win or lose multiple games. Total games win by B is 50 and the ratio of game win by A and games lose by B is 3:2 respectively. The ratio of total games loses by A to total games win by A is 4:3. The average of number of games lose by A and win by B is 105. Total games win by C is 20% more than total games loss of B and the ratio of total games win to lose by C is 4 : 5.
Find the ratio of the total games win by A and the total games lose by C.
- A.
2:1
- B.
1:1
- C.
1:3
- D.
4:3
- E.
5:2
Show answer & explanation
Correct answer: B
Concept
In ratio-based data interpretation, every unknown quantity is anchored to a known one through the given ratios and averages. The governing identities here are: average of two values = (their sum) / 2; if x : y = a : b then x = y x (a/b); and "p% more than n" means n x (1 + p/100). Find one concrete value first, then propagate it through the chain of ratios.
Application
Games won by B is given directly as 50.
Average of (games lost by A) and (games won by B) is 105, so games lost by A = 105 x 2 - 50 = 160.
Games lost by A : games won by A = 4 : 3, so games won by A = 160 x 3/4 = 120.
Games won by A : games lost by B = 3 : 2, so games lost by B = 120 x 2/3 = 80 (this is consistent with the 3:2 link, confirming 120).
Games won by C is 20% more than games lost by B = 80 x 1.20 = 96.
Games won by C : games lost by C = 4 : 5, so games lost by C = 96 x 5/4 = 120.
Required ratio = games won by A : games lost by C = 120 : 120 = 1 : 1.
Cross-check
Independent verification: games won by A (120) and games lost by C (120) are equal, so their ratio must reduce to 1 : 1. Re-deriving lost-by-B from won-by-C (96 / 1.20 = 80) and won-by-A from lost-by-B (80 x 3/2 = 120) returns the same 120, so the chain is internally consistent and the ratio is 1 : 1.