The pie chart (i) given below shows percentage distribution of total people…
2023
The pie chart
(i) given below shows percentage distribution of total people (male + female) visited five different clubs and pie chart
(ii) shows percentage distribution of total male visited in these five clubs. Read the data carefully and answer the questions given below.
The average number of females visited clubs B, E and X is 126. If total males visited club X are 45% of total males visited club A, then find the difference between total number of people visited club X and total females visited clubs A and C together.
- A.
198
- B.
218
- C.
208
- D.
168
- E.
178
Show answer & explanation
Correct answer: C
Concept
In a two-pie data-interpretation set, each sector percentage is converted to an absolute count by multiplying it with the chart's stated total. Here pie (i) splits Total people = 2500 and pie (ii) splits Total males = 1200, so for any club: Females = (people-share x 2500) - (male-share x 1200). An 'average of three quantities = k' means their sum is 3k, which lets you recover a single unknown count once the other two are known.
Application
Convert the needed sectors to counts, then apply the two conditions in order:
Total people: A = 24% x 2500 = 600, B = 16% x 2500 = 400, C = 18% x 2500 = 450, E = 12% x 2500 = 300.
Males: A = 20% x 1200 = 240, B = 15% x 1200 = 180, C = 35% x 1200 = 420, E = 18% x 1200 = 216.
Females = people - males: A = 600 - 240 = 360, B = 400 - 180 = 220, C = 450 - 420 = 30, E = 300 - 216 = 84.
Condition 1 (average of females in B, E, X is 126): Females(B) + Females(E) + Females(X) = 3 x 126 = 378, so Females(X) = 378 - 220 - 84 = 74.
Condition 2 (males in X are 45% of males in A): Males(X) = 0.45 x 240 = 108.
Total people in X = Males(X) + Females(X) = 108 + 74 = 182.
Females in A and C together = 360 + 30 = 390.
Required difference = 390 - 182 = 208.
Cross-check
Independently: Total X (182) sits below Females(A)+Females(C) (390), and 390 - 182 = 208, matching the keyed value. Note club C has very few females (30) because its male share (35% of 1200 = 420) nearly fills its small people count (450) - a deliberate trap that makes Females(A)+Females(C) dominated by A; mishandling C's low female count shifts the result away from 208.