Direction : Given data shows total male and female employee in three companies…
2020
Direction : Given data shows total male and female employee in three companies in a seminar. Read data carefully and answer the questions:-
In annual seminar of three companies, A, B and C some male and female employees represent their companies. Average number of female employees who represent A and B is 420. Total male employee in A and B is 1620. Number of female employees is ⅔ rd and ⅖ th of male employee in A and B respectively. Total female employee who represent C are 25% more than total female employee who represent A and total male employee who represent C are 33 ⅓ % more than total female employee who represent B.
25% of total female employee and 20% of total male employee who represent B & C together have
MBA degree, then find total employee who do not have MBA degree?
- A.
1624
- B.
1424
- C.
1824
- D.
1648
- E.
1244
Show answer & explanation
Correct answer: C
Concept
In two-variable data interpretation, every unknown count is fixed by translating each verbal relation into one linear equation, then solving the system. A stated fraction "x is two-thirds of y" means x = (2/3)y; "p% more than y" means y multiplied by (1 + p/100). "Do not have a degree" equals the whole group minus those who do.
Setting up A and B
Average female of A and B is 420, so female(A) + female(B) = 2 x 420 = 840.
Total male of A and B is 1620, so male(A) + male(B) = 1620.
Female is two-thirds of male in A and two-fifths of male in B: female(A) = (2/3)male(A), female(B) = (2/5)male(B).
Substitute into the female sum: (2/3)male(A) + (2/5)male(B) = 840, with male(A) + male(B) = 1620.
Solving gives male(B) = 900, male(A) = 720; hence female(A) = 480 and female(B) = 360.
Building C
Female(C) is 25% more than female(A): 480 x 1.25 = 600.
Male(C) is 33 1/3% more than female(B): 360 x (4/3) = 480.
B and C together
Combine the two companies named in the question.
Group | Female | Male |
|---|---|---|
B | 360 | 900 |
C | 600 | 480 |
Total | 960 | 1380 |
Applying the MBA percentages
Female with MBA in B and C: 25% of 960 = 240.
Male with MBA in B and C: 20% of 1380 = 276.
Total with MBA = 240 + 276 = 516.
Total employees in B and C = 960 + 1380 = 2340.
Employees without MBA = 2340 - 516 = 1824.
Cross-check
Verify the counts: female(A)=480 is two-thirds of male(A)=720, and female(B)=360 is two-fifths of male(B)=900, and 480+360=840, 720+900=1620 - all constraints hold. The MBA holders (516) plus non-MBA (1824) recover the full B and C strength of 2340, confirming 1824.