Find the zeros of the quadratic polynomial √3x² − 8x + 4√3.

Solve √3 x² − 8x + 4√3 = 0 using the quadratic formula with a = √3, b = −8, c = 4√3.

1. Compute the discriminant: Δ = b² − 4ac = (−8)² − 4(√3)(4√3) = 64 − 48 = 16, so √Δ = 4.

2. Apply the quadratic formula: x = [−b ± √Δ]/(2a) = [8 ± 4]/(2√3).

3. Calculate the two roots: (8 + 4)/(2√3) = 12/(2√3) = 6/√3 = 2√3, and (8 − 4)/(2√3) = 4/(2√3) = 2/√3.

Zeros: 2√3 and 2/√3