A block of addresses is granted to a small organization. If one of the…
2017
A block of addresses is granted to a small organization. If one of the addresses is 210.32.64.79/26, then what will be the values of the following?
(i) First address
(ii) Last address
(iii) Total number of addresses
- A.
(i) 210.32.64.64, (ii) 210.32.64.127, (iii) 64
- B.
(i) 210.32.64.64, (ii) 210.32.64.255, (iii) 32
- C.
(i) 210.32.64.79, (ii) 210.32.64.255, (iii) 64
- D.
(i) 210.32.64.64, (ii) 210.32.64.79, (iii) 128
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Correct answer: A
The correct option is A. For CIDR block 210.32.64.79/26, the subnet mask uses 26 bits. Total host bits = 32 - 26 = 6. Total addresses = 2^6 = 64. The last octet 79 in binary is 01001111. Keeping network bits unchanged: First address (host bits all 0) = 210.32.64.64. Last address (host bits all 1) = 210.32.64.127.