. Ten signals, each requiring 3000 Hz, are multiplexed onto a single channel…
2017
. Ten signals, each requiring 3000 Hz, are multiplexed onto a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel? Assume that the guard bands are 300 Hz wide.
Answer: C. 32,700 — Number of signals = 10 Bandwidth of each signal = 3000 Hz Total signal bandwidth = 10 × 3000 = 30,000 Hz Number of guard bands = 10 − 1 = 9 Bandwidth of each…
- A.
33,700
- B.
30,000
- C.
32,700
- D.
33,000
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Correct answer: C
Number of signals = 10
Bandwidth of each signal = 3000 Hz
Total signal bandwidth = 10 × 3000 = 30,000 Hz Number of guard bands = 10 − 1 = 9
Bandwidth of each guard band = 300 Hz
Total guard band bandwidth = 9 × 300 = 2700 Hz Total required bandwidth = Signal bandwidth + Guard band bandwidth = 30,000 + 2,700 = 32,700 Hz