A transient of 100 ms is to be captured on a digital storage oscilloscope on…
2013
A transient of 100 ms is to be captured on a digital storage oscilloscope on full screen in the horizontal direction. If the transient is to be recorded at a sampling rate of 100 KS/s, what should the minimum size of the acquisition memory be?
- A.
5K
- B.
10K
- C.
15K
- D.
20K
Attempted by 75 students.
Show answer & explanation
Correct answer: B
Given: sampling rate f_s = 100 KS/s = 100,000 samples/s; transient duration T_rec = 100 ms = 0.1 s.
Formula: number of samples N = f_s × T_rec
Step 1: Convert units: 100 KS/s = 100,000 samples/s; 100 ms = 0.1 s.
Step 2: Compute N = 100,000 × 0.1 = 10,000 samples.
Answer: minimum acquisition memory = 10,000 samples (10K).