The following grammar is: S → Aa | bAc | Bc | bBa A → d B → d

2019

The following grammar is:

S → Aa | bAc | Bc | bBa
A → d
B → d

Answer: D. LR(1) but not LALR(1)

  1. A.

    Not LR(1) but LALR(1)

  2. B.

    Neither LR(1) nor LALR(1)

  3. C.

    LR(1) and LALR(1)

  4. D.

    LR(1) but not LALR(1)

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Correct answer: D

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