Negation of the proposition \(βˆƒπ‘₯𝐻(π‘₯)\) is

2017

Negation of the propositionΒ \(βˆƒπ‘₯𝐻(π‘₯)\)Β is

  1. A.

    \(\exists \: x \: \neg \: H(x)\)

  2. B.

    \(\forall \: x \: \neg \: H(x)\)

  3. C.

    \(\forall \: x \: H(x)\)

  4. D.

    \(\neg \: x \: H(x)\)

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Correct answer: B

Answer: βˆ€x Β¬H(x).

Reason: By the quantifier negation rule, not-exists becomes for-all-not: Β¬(βˆƒx H(x)) ≑ βˆ€x Β¬H(x). Intuitively, saying "it is not the case that some x has property H" means "every x does not have property H."

  • Common incorrect alternative: βˆƒx Β¬H(x) states that there exists at least one x without H, which is not equivalent to saying no x has H.

  • Example to see the difference: if H(1) = true and H(2) = false, then βˆƒx H(x) is true and its negation is false, but βˆƒx Β¬H(x) is true. So βˆƒx Β¬H(x) does not capture the negation of βˆƒx H(x).

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