Negation of the proposition \(βπ₯π»(π₯)\) is
2017
Negation of the propositionΒ \(βπ₯π»(π₯)\)Β is
- A.
\(\exists \: x \: \neg \: H(x)\) - B.
\(\forall \: x \: \neg \: H(x)\) - C.
\(\forall \: x \: H(x)\) - D.
\(\neg \: x \: H(x)\)
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Correct answer: B
Answer: βx Β¬H(x).
Reason: By the quantifier negation rule, not-exists becomes for-all-not: Β¬(βx H(x)) β‘ βx Β¬H(x). Intuitively, saying "it is not the case that some x has property H" means "every x does not have property H."
Common incorrect alternative: βx Β¬H(x) states that there exists at least one x without H, which is not equivalent to saying no x has H.
Example to see the difference: if H(1) = true and H(2) = false, then βx H(x) is true and its negation is false, but βx Β¬H(x) is true. So βx Β¬H(x) does not capture the negation of βx H(x).
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