Match List I with List II List I (a) p → q (b) p ∨ q (c) p ∧ q (d) (p → q)’…
2019
Match List I with List II
List I
(a) p → q
(b) p ∨ q
(c) p ∧ q
(d) (p → q)’
List II
(i) (p → q)’
(ii) p ∧ q’
(iii) p’ → q
(iv) p’ ∨ q
- A.
(a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
- B.
(a)-(ii), (b)-(i), (c)-(iii), (d)-(iv)
- C.
(a)-(iv), (b)-(i), (c)-(iii), (d)-(ii)
- D.
(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
Attempted by 56 students.
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Correct answer: D
The implication p → q is logically equivalent to ¬p ∨ q. In List II, item (iv) represents p' ∨ q, matching the standard definition of implication. Thus, Option 3 is correct.
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