Match the LIST-I with LIST-II : BOOLEAN IDENTITIES LIST-I (Name) LIST-II…
2026
Match the LIST-I with LIST-II : BOOLEAN IDENTITIES
LIST-I (Name) | LIST-II (Identity) |
A. Domination law | I. x + 1 = 1 |
B. Associative law | II. x + (yz) = (x + y)(x + z) |
C. Distributive law | III. x + xy = x |
D. Absorption law | IV. x + (y + z) = (x + y) + z |
Choose the correct answer from the options given below:
A-I, B-II, C-IV, D-III
A-I, B-IV, C-II, D-III
A-III, B-IV, C-II, D-I
A-III, B-II, C-IV, D-I
- A.
1
- B.
2
- C.
3
- D.
4
Attempted by 426 students.
Show answer & explanation
Correct answer: B
To solve this, we match each Boolean law with its corresponding identity: 1. Domination Law: States that x + 1 = 1 and x · 0 = 0. This matches I. 2. Associative Law: States that grouping does not matter, e.g., x + (y + z) = (x + y) + z. This matches IV. 3. Distributive Law: States x + (y · z) = (x + y)(x + z) in Boolean algebra. This matches II. 4. Absorption Law: States x + xy = x. This matches III. Thus, the correct matching is A-I, B-IV, C-II, D-III.