The Simplified form of a Boolean equation (AB'+AB'C+AC)(A'C'+B') is:

First, simplify (AB' + AB'C) by factoring out AB', resulting in AB'(1+C). Since 1+C equals 1, this term reduces to AB'. The expression becomes (AB' + AC)(A'C' + B'). Expanding this yields AB'A'C', AB'B', ACA'C', and ACB'. Terms containing AA' or A'A evaluate to 0, leaving AB' + AB'C. Finally, factor out AB' again to confirm the simplified form is AB'. This matches Option 0.