Match List I with II \(L_R:\) Regular language, \(𝐿𝐶𝐹\): Context free…

2020

Match List I with II

\(L_R:\) Regular language, \(𝐿𝐶𝐹\): Context free language

\(L_{REC}:\) Recursive langauge,  \(L_{RE} : \) Recursively enumerable language.

\(\begin{array}{llll} & \text{List I} & & \text{List II} \\ (A) & \text{Recursively Enumerable language} & (I) & \overline{L}_{REC} \cup L_{RE} \\ (B) & \text{Recursive language} & (II) & \overline{L}_{CF} \cup L_{REC} \\ (C) & \text{Context Free language} & (III) & L_R^* \cap L_{CF} \end{array}\)

Choose the correct answer from the options given below:

  1. A.

    \(A-II, B-III, C-I\)

  2. B.

    \(A-III, B-I, C-II\)

  3. C.

    \(A-I, B-II, C-III\)

  4. D.

    \(A-II, B-I, C-III\)

Attempted by 44 students.

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Correct answer: C

Answer: Recursively Enumerable -> (I), Recursive -> (II), Context Free -> (III).

  • Explanation for (I):

    Let the symbol L_REC denote a particular recursive (decidable) language and L_RE denote a particular recursively enumerable language. The complement of a recursive language is recursive because recursive languages are closed under complementation. Since every recursive language is also recursively enumerable, the union of a recursive language and a recursively enumerable language is recursively enumerable. Therefore the expression "complement of L_REC union L_RE" denotes a recursively enumerable language.

  • Explanation for (II):

    Take L_CF as a particular context-free language. All context-free languages are decidable (they lie inside the recursive class), so the complement of a context-free language is recursive. The union of two recursive languages is recursive. Hence "complement of L_CF union L_REC" denotes a recursive language.

  • Explanation for (III):

    If L_R is a regular language, then L_R starred (Kleene star) is still regular. The intersection of a regular language with a context-free language is a context-free language because context-free languages are closed under intersection with regular languages. Therefore "L_R^* intersect L_CF" denotes a context-free language.

  • Conclusion: Putting these results together yields the matching Recursively Enumerable -> (I), Recursive -> (II), Context Free -> (III).

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