Consider the following Finite Automata. Which of the following is not a…

The Finite Automata accepts strings that end in state q1, which requires the last symbol to be 'a'. Option C (b* ab*(ab*ab*)*) is incorrect because its structure allows the string to end in state q0. The initial segment b* a b* transitions from the start state back to itself, and the loop (ab* ab*)* also cycles between q0 and returns to q0. Consequently, this expression generates strings ending in 'b', not 'a'. In contrast, Options A, B, and D all ensure the final transition lands on q1. For instance, Option A (a + b)* a explicitly ends with 'a', and Option D (b + aa*b)* aa* ensures the last part is 'aa*', which also ends in 'a'. Therefore, Option C fails to describe the language accepted by the automaton.