A system has 99.99% uptime and has a mean‐time‐between‐failure of 1 day. How…

2021

A system has 99.99% uptime and has a mean‐time‐between‐failure of 1 day. How fast does the system has to repair itself in order to reach this availability goal?

  1. A.

    - 9 Seconds

  2. B.

    -10 Seconds

  3. C.

    -11 Seconds

  4. D.

    -12 Seconds

Attempted by 84 students.

Show answer & explanation

Correct answer: A

Goal: Find the required mean-time-to-repair (MTTR) to achieve 99.99% availability given MTBF = 1 day.

Formula: A = MTBF / (MTBF + MTTR)

Solve for MTTR:

  • MTTR = MTBF * (1 - A) / A

  • Convert MTBF to seconds: 1 day = 86,400 s

  • Plug in A = 0.9999 and MTBF = 86,400 s:

  • MTTR = 86,400 * (1 - 0.9999) / 0.9999 = 86,400 * 0.0001 / 0.9999

  • Compute numerator: 86,400 * 0.0001 = 8.64

  • Divide: 8.64 / 0.9999 ≈ 8.640864... seconds

Conclusion: The required MTTR is approximately 8.64 seconds (about 9 seconds).

Note: To strictly meet 99.99% availability the MTTR must be less than or equal to 8.640864 s. Using a rounded value of 9 s yields availability ≈ 99.9896%, which is marginally below 99.99%.

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