A system has 99.99% uptime and has a mean‐time‐between‐failure of 1 day. How…
2021
A system has 99.99% uptime and has a mean‐time‐between‐failure of 1 day. How fast does the system has to repair itself in order to reach this availability goal?
- A.
- 9 Seconds
- B.
-10 Seconds
- C.
-11 Seconds
- D.
-12 Seconds
Attempted by 84 students.
Show answer & explanation
Correct answer: A
Goal: Find the required mean-time-to-repair (MTTR) to achieve 99.99% availability given MTBF = 1 day.
Formula: A = MTBF / (MTBF + MTTR)
Solve for MTTR:
MTTR = MTBF * (1 - A) / A
Convert MTBF to seconds: 1 day = 86,400 s
Plug in A = 0.9999 and MTBF = 86,400 s:
MTTR = 86,400 * (1 - 0.9999) / 0.9999 = 86,400 * 0.0001 / 0.9999
Compute numerator: 86,400 * 0.0001 = 8.64
Divide: 8.64 / 0.9999 ≈ 8.640864... seconds
Conclusion: The required MTTR is approximately 8.64 seconds (about 9 seconds).
Note: To strictly meet 99.99% availability the MTTR must be less than or equal to 8.640864 s. Using a rounded value of 9 s yields availability ≈ 99.9896%, which is marginally below 99.99%.
A video solution is available for this question — log in and enroll to watch it.