Consider a logical address space of 8 pages of 1024 words mapped with memory…
2011
Consider a logical address space of 8 pages of 1024 words mapped with memory of 32 frames. How many bits are there in the physical address
- A.
9 bits
- B.
11 bits
- C.
13 bits
- D.
15 bits
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Correct answer: D
The physical address is composed of the frame number and the page offset. Since there are 32 frames, the frame number requires five bits because log base two of thirty-two equals five. The page size is 1024 words, requiring ten bits for the offset since log base two of one thousand twenty-four equals ten. Adding these together yields a total physical address size of fifteen bits.
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