Consider the following processes with time slice of 4 milliseconds (I/O…
2013
Consider the following processes with time slice of 4 milliseconds (I/O requests are ignored):
The average turnaround time of these processes will be
- A.
19.25 milliseconds
- B.
18.25 milliseconds
- C.
19.5 milliseconds
- D.
18.5 milliseconds
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Correct answer: B
Using Round Robin scheduling with a time slice of 4ms, we trace the execution to find completion times. Process B finishes at t=8, A at t=21, D at t=27, and C at t=28. Turnaround Time (TAT) is Completion Time minus Arrival Time: A(21-0)=21, B(8-1)=7, C(28-2)=26, D(27-3)=24. The sum of TATs is 78, so the average is 19.5 ms.
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