Consider the following set of processes with the length of CPU burst time in…

First, list the burst times: A=6, B=1, C=2, D=1, E=5. With a 1ms time slice and arrival order A-B-C-D-E:

1. A runs (5 left), B runs (done at 2ms). 2. C runs (1 left), D runs (done at 4ms). 3. E runs (4 left), A runs (4 left). 4. C runs (done at 7ms), E runs (3 left).

5. A runs (3 left), E runs (2 left). 6. A runs (2 left), E runs (1 left). 7. A runs (1 left), E runs (done at 14ms). 8. A runs (done at 15ms).

Completion times: B=2, D=4, C=7, E=14, A=15. Turnaround times are equal to completion times (AT=0). Average TAT = (2+4+7+14+15)/5 = 8.4 ms.