A 4-stage pipeline has the stage delay as 150,120,160 and 140 ns respectively.…

Solution:

• Determine the clock period: it equals the slowest stage delay plus the register delay.

• Slowest stage delay = 160; register delay = 5; therefore clock period = 160 + 5 = 165 (in the same units as the given delays).

• Compute total cycles required: for a p-stage pipeline processing N items, cycles = p + N - 1.

• Here p = 4 and N = 1000, so cycles = 4 + 1000 - 1 = 1003 cycles.

• Total time = number of cycles × clock period = 1003 × 165 = 165495 (in the same units as the stage delays).

Unit clarification and final numeric answer:

If the stage and register delays are in nanoseconds, the total time = 165495 ns = 0.165495 ms (≈ 0.1655 ms).

If the problem intends the delays to be in microseconds (which matches the provided choices), the total time = 165495 µs = 165.495 ms ≈ 165.5 ms.

Therefore, under the intended unit interpretation, the correct numeric choice is 165.5 ms.