Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50…
2020
Concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double-sided platters, and average seek time of 10 milliseconds.
If 𝑇 is the capacity of a track in bytes, and 𝑆 is the capacity of each surface in bytes, then (𝑇,𝑆) = _______
- A.
(50𝐾,50000𝐾)
- B.
(25𝐾,25000𝐾)
- C.
(25𝐾,50000𝐾)
- D.
(40𝐾,36000𝐾)
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Correct answer: C
Calculation: compute capacity per track and per surface.
T (capacity per track) = sector size × sectors per track = 512 bytes × 50 = 25,600 bytes = 25 K (K = 1024 bytes).
S (capacity per surface) = T × number of tracks per surface = 25,600 bytes × 2000 = 51,200,000 bytes = 50,000 K.
Answer: (25K, 50000K).
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