The question given below concern a disk with a sector size of 512 bytes, 2000…
2020
The question given below concern a disk with a sector size of 512 bytes, 2000 tracks per surface, 50 sectors per track, five double sided platters, and average seek time of 10 milliseconds
If the disk platters rotate at 5400 rpm, then approximately what is the maximum rotational delay
- A.
0.011 seconds
- B.
0.11 seconds
- C.
0.0011 seconds
- D.
1.1 seconds
Attempted by 38 students.
Show answer & explanation
Correct answer: A
The maximum rotational delay equals the time required for one full disk rotation. With a speed of 5400 rpm, the period is calculated as 60 divided by 5400, which equals approximately 0.0111 seconds.
A video solution is available for this question — log in and enroll to watch it.