Match the terms in List-I with the options given in List-II :…
2018
Match the terms in List-I with the options given in List-II :
\(\begin{array}{clcl} & \textbf{List-I} & & \textbf{List-II}\\ \text{(a)} & \text{Decoder} &\text{(i)} & \text{1 line to $2^n$ lines} \\ \text{(b)} & \text{Multiplexer} & \text{(ii)} & \text{n lines to $2^n$ lines} \\ \text{(c)} & \text{De multiplexer} & \text{(iii)} &\text{$2^n$ lines to 1 line} \\ &&\text{(iv)}& \text{$2^n$ lines to $2^{n-1}$ lines} \\ \end{array}\)
\(Code :\)
- A.
(a)-(ii); (b)-(i); (c)-(iii)
- B.
(a)-(ii); (b)-(iii); (c)-(i)
- C.
(a)-(ii); (b)-(i); (c)-(iv)
- D.
(a)-(iv);(b)-(ii); (c)-(i)
Attempted by 423 students.
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Correct answer: B
Correct matching: Decoder → n lines to 2^n lines; Multiplexer → 2^n lines to 1 line; Demultiplexer → 1 line to 2^n lines.
Decoder: converts an n-bit binary input into 2^n distinct outputs, so exactly one of the 2^n outputs is activated for each input code (n lines to 2^n lines).
Multiplexer: selects one line from many input lines and forwards it to a single output (many-to-one). For a 2^n-input multiplexer this is 2^n lines to 1 line.
Demultiplexer: takes a single input and routes it to one of many outputs (one-to-many). For a demultiplexer with 2^n outputs this is 1 line to 2^n lines.
Therefore the correct matching is: Decoder — n lines to 2^n lines; Multiplexer — 2^n lines to 1 line; Demultiplexer — 1 line to 2^n lines.
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