Consider the following relations X(S, Si, C) and Y(S, P, D) . Result of \(X ⟖…

Solution: Compute the right outer join of X and Y on the attribute S.

• Join condition: X.S = Y.S. The operator is a right outer join, so preserve every tuple from the right relation Y; include attributes from X when a match exists, otherwise set X attributes to NULL.

• Result schema: S, Si, C, P, D.

• Resulting tuples:

• J: Si = 1, C = M, P = S1, D = CA

• B: Si = 2, C = N, P = P1, D = AB

• R: Si = 3, C = H, P = D1, D = DC

• A: Si = NULL, C = NULL, P = H1, D = MD

• Note: The tuple with S = T from X is not included because T does not appear in Y; the right outer join preserves Y tuples (including S = A) and uses NULLs for nonmatching attributes from X.