A neuron with inputs has the weight vector \(\begin{bmatrix}0.2 & -0.1 & 0.1…
2017
A neuron with inputs has the weight vector \(\begin{bmatrix}0.2 & -0.1 & 0.1 \end{bmatrix}^T\) and a bias \(\theta =0\). If the input vector is \(X = \begin{bmatrix}0.2 & 0.4 & 0.2 \end{bmatrix}^T\). Then the total input to the neuron is:
- A.
0.20
- B.
1.0
- C.
0.02
- D.
-1.0
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Correct answer: C
Solution: Compute the total input (net input) as the dot product of the weight vector and the input vector, plus the bias (here bias = 0).
Multiply corresponding components:
0.2 × 0.2 = 0.04; (−0.1) × 0.4 = −0.04; 0.1 × 0.2 = 0.02.
Sum the products and add the bias:
0.04 + (−0.04) + 0.02 + 0 = 0.02.
Therefore the total input to the neuron is 0.02.