The correct way to round off a floating number x to an integer value is
2013
The correct way to round off a floating number x to an integer value is
- A.
y = (int) (x + 0.5)
- B.
y = int (x + 0.5)
- C.
y = (int) x + 0.5
- D.
y = (int) ((int)x + 0.5)
Attempted by 1022 students.
Show answer & explanation
Correct answer: A
Correct expression: y = (int) (x + 0.5)
Why this works (for non-negative values):
Adding 0.5 shifts numbers with fractional part 0.5 or greater up to the next integer threshold.
Casting to integer then truncates the fractional part, producing the expected rounded integer.
Example: x = 2.3 → x + 0.5 = 2.8 → (int)(2.8) = 2; x = 2.6 → x + 0.5 = 3.1 → (int)(3.1) = 3.
Important caveats and alternatives:
For negative numbers this method may fail because many languages truncate toward zero when casting. For example, x = -2.6: x + 0.5 = -2.1 and casting toward zero gives -2, while mathematically rounding should give -3.
Behavior is language-dependent: in Python, int(x+0.5) resembles this approach but still truncates toward zero for negatives. Prefer using the language-provided round function (for example round(x) in many languages) which handles sign correctly.
If you need mathematical rounding (round half up) that works for negatives, use floor(x + 0.5) for real-to-integer conversion when floor is defined to be the mathematical floor, or use a dedicated rounding routine.
Summary: The expression y = (int) (x + 0.5) correctly rounds non-negative floating values in the usual cast-truncate languages. For robust behavior across positive and negative values, prefer built-in round functions or a floor-based approach.
A video solution is available for this question — log in and enroll to watch it.