The correct way to round off a floating number x to an integer value is

2013

The correct way to round off a floating number x to an integer value is

  1. A.

    y = (int) (x + 0.5)

  2. B.

    y = int (x + 0.5)

  3. C.

    y = (int) x + 0.5

  4. D.

    y = (int) ((int)x + 0.5)

Attempted by 1022 students.

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Correct answer: A

Correct expression: y = (int) (x + 0.5)

Why this works (for non-negative values):

  • Adding 0.5 shifts numbers with fractional part 0.5 or greater up to the next integer threshold.

  • Casting to integer then truncates the fractional part, producing the expected rounded integer.

  • Example: x = 2.3 → x + 0.5 = 2.8 → (int)(2.8) = 2; x = 2.6 → x + 0.5 = 3.1 → (int)(3.1) = 3.

Important caveats and alternatives:

  • For negative numbers this method may fail because many languages truncate toward zero when casting. For example, x = -2.6: x + 0.5 = -2.1 and casting toward zero gives -2, while mathematically rounding should give -3.

  • Behavior is language-dependent: in Python, int(x+0.5) resembles this approach but still truncates toward zero for negatives. Prefer using the language-provided round function (for example round(x) in many languages) which handles sign correctly.

  • If you need mathematical rounding (round half up) that works for negatives, use floor(x + 0.5) for real-to-integer conversion when floor is defined to be the mathematical floor, or use a dedicated rounding routine.

Summary: The expression y = (int) (x + 0.5) correctly rounds non-negative floating values in the usual cast-truncate languages. For robust behavior across positive and negative values, prefer built-in round functions or a floor-based approach.

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