For implicit type conversion, arrange the following from a lower size type to…

To solve this, we must arrange the data types based on their memory size in ascending order (from smallest to largest).

Step 1: Analyze Type Sizes

Assuming a standard 32-bit system architecture:

• unsigned int: 4 bytes

• unsigned long int: 4 bytes (on 32-bit) or 8 bytes (on 64-bit). However, in standard implicit conversion hierarchies, unsigned int is often treated as the base before long types.

• long int: 4 bytes (on 32-bit) or 8 bytes (on 64-bit). Typically, long int is equal to or larger than unsigned int.

• double: 8 bytes

• long double: 12 bytes or 16 bytes (largest among these).

Step 2: Determine the Correct Order

The standard hierarchy for implicit conversion (promoting smaller types to larger types) generally follows this size progression:

• 1. unsigned int (Smallest integer type listed)

• 2. unsigned long int (Larger or equal to unsigned int)

• 3. long int (Integer type, often same size as unsigned long int but conceptually follows in hierarchy)

• 4. double (Floating point, 8 bytes)

• 5. long double (Largest floating point type)

Therefore, the correct arrangement from lower size to high type size is: unsigned int (C) → unsigned long int (B) → long int (E) → double (A) → long double (D).

This corresponds to the sequence: C, B, E, A, D.