What will be the output of the following code?
#include <stdio.h>
int main()
{
int a, b, c;
a = 0x10;
b = 010;
c = a + b;
printf("%d", c);
return 0;
}

Question

What will be the output of the following code? #include <stdio.h> int main() { int a, b, c; a = 0x10; b = 010; c = a + b; printf("%d", c); return 0; }

Accepted Answer

Correct answer: B — Final output: 24 Explanation: 0x10 is a hexadecimal literal. In decimal, 0x10 = 16. 010 is an octal literal because it starts with a leading 0. In decimal, 010 (octal) = 8. Add the values: 16 + 8 = 24. printf("%d", c) prints the decimal value of c, so the program outputs 24. Note: The code is valid C; there is no runtime garbage or compilation error in this example.

Answer

A. 20

Answer

B. 24

Answer

C. Garbage

Answer

D. Error

What will be the output of the following code? #include <stdio.h> int main() {…