What is x in the following program?
#include <stdio.h>
int main(void)
{
typedef int (*(*arrfptr[3])())[10];
arrfptr x;
return 0;
}

Question

What is x in the following program? #include <stdio.h> int main(void) { typedef int (*(*arrfptr[3])())[10]; arrfptr x; return 0; }

Accepted Answer

Correct answer: C — Final answer: x is an array of three function pointers. Each function returns a pointer to an array of 10 int values. The declaration is typedef int (*(*arrfptr[3])())[10]; Read it from arrfptr outward. arrfptr[3] means an array of three elements. Each element is a pointer to a function. The function return type is int (*)[10], a pointer to an array of 10 integers. Therefore, arrfptr x; declares x as an array[3] of pointers to functions returning int (*)[10].

Answer

A. x is pointer

Answer

B. x is an array of three pointers

Answer

C. x is an array of three function pointers

Answer

D. Error in x declaration

What is x in the following program? #include <stdio.h> int main(void) {…