What will be the output of the following C Programming code:
Void main()
{
Int *i, a=12, b=2,c;
c=(a=a+b, b=a/b, a=a*b, b=a-b);
i=&c;
printf(“%d”,--(*i));
}

Question

What will be the output of the following C Programming code: Void main() { Int *i, a=12, b=2,c; c=(a=a+b, b=a/b, a=a*b, b=a-b); i=&c; printf(“%d”,--(*i)); }

Accepted Answer

Correct answer: B — Step-by-step evaluation of c = (a = a + b, b = a / b, a = a * b, b = a - b): Start with a = 12, b = 2. a = a + b => a becomes 14. b = a / b => b becomes 14 / 2 = 7. a = a * b => a becomes 14 * 7 = 98. b = a - b => b becomes 98 - 7 = 91. The comma operator yields the value of the last expression, so c is assigned 91. i points to c. The expression --(*i) pre-decrements c to 90 and that decremented value (90) is printed. Final output: 90

Answer

A. 91

Answer

B. 90

Answer

C. 98

Answer

D. 92

What will be the output of the following C Programming code: Void main() { Int…