A survey of 50 cars was conducted for the features air conditioning, radio,…

2016

A survey of 50 cars was conducted for the features air conditioning, radio, and power windows. The following information was found:

  • 30 cars had air conditioning.

  • 4 cars had air conditioning and power windows but no radio.

  • 21 cars had radio.

  • 12 cars had radio and air conditioning but no power windows.

  • 20 cars had power windows.

  • 1 car had radio and power windows but no air conditioning.

  • 6 cars had all three features.

How many cars had none of these three features?

Answer: B. 8ConceptFor three sets, inclusion–exclusion gives the size of their union by adding the three single-set totals, subtracting the three pairwise intersections,…

  1. A.

    6

  2. B.

    8

  3. C.

    10

  4. D.

    4

Attempted by 243 students.

Show answer & explanation

Correct answer: B

Concept

For three sets, inclusion–exclusion gives the size of their union by adding the three single-set totals, subtracting the three pairwise intersections, and then adding the triple intersection once.

A count stated as “in A and B but not C” is an exclusive two-set region. Add the triple-overlap count to it before using it as an inclusive pairwise intersection.

Application

  1. Let A, R, and P denote cars with air conditioning, radio, and power windows. The inclusive pairwise intersections are |A∩R| = 12 + 6 = 18, |A∩P| = 4 + 6 = 10, and |R∩P| = 1 + 6 = 7.

  2. Apply inclusion–exclusion: |A∪R∪P| = 30 + 21 + 20 − 18 − 10 − 7 + 6.

  3. Evaluate the union: |A∪R∪P| = 42. Thus, 42 cars have at least one of the three features.

  4. Take the complement in the surveyed total: 50 − 42 = 8 cars have none of the three features.

Cross-check

Compute the seven disjoint regions and verify that their sum equals the union:

Region

Count

Air conditioning only

30 − 12 − 4 − 6 = 8

Radio only

21 − 12 − 1 − 6 = 2

Power windows only

20 − 4 − 1 − 6 = 9

Exactly A and R

12

Exactly A and P

4

Exactly R and P

1

All three

6

The disjoint-region sum is 8 + 2 + 9 + 12 + 4 + 1 + 6 = 42, so the complement is again 8.

Result

8 cars had none of the three features.

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