A, B, C, D, E, F and G are sitting in a row facing North : F is to the…

In a linear seating puzzle, translate each relative clue — 'nth to the right/left', 'immediate right', 'neighbour of' — into a position equation. First use the clue that anchors an absolute position (here, a clue tied to a row end) to fix one person's exact seat, then resolve the rest using the neighbour/adjacency constraints, rejecting any combination that produces a clash.

1. The person third to the left of D is at an end, so D's position minus 3 equals the left end (position 1) — this fixes D at position 4.

2. E is 4th to the right of G, so E = G + 4. With 7 seats, the only workable pairs are G = 1, E = 5 or G = 2, E = 6.

3. F is immediate right of E, so F = E + 1, giving F = 6 (if E = 5) or F = 7 (if E = 6).

4. C is the neighbour of both B and D, so with D fixed at position 4, C must sit at position 3 or position 5, with B on C's other side.

5. Testing G = 1, E = 5, F = 6 with C = 3, B = 2: no seat clashes — positions 2, 3, 4, 5, 6 are all distinct (B, C, D, E, F), leaving position 7 for A.

6. Testing G = 2, E = 6, F = 7 (with C = 5, B = 6 as the alternative) each collides with an already-fixed seat, so both alternatives are rejected.

Verifying the arrangement G, B, C, D, E, F, A against every clue: F sits immediately right of E (position 6 is right of position 5); E is 4th right of G (5 minus 1 = 4); C at position 3 is neighboured by B at position 2 and D at position 4; the person third to the left of D (position 1) is the left end — all four conditions hold.

The people seated to C's left are therefore G and B.