Directions: Study the following information carefully and answer the questions…

Concept: In a circular seating arrangement, pick one fixed direction of travel around the circle to mean 'right' (and the opposite direction to mean 'left') and apply that SAME sense consistently to every clue — the absolute compass/clockwise sense does not matter, only that all 'k-th to the left/right' clues are read the same way. Fix one person as a reference point (position 0), convert every clue into a numeric offset around the circle (wrapping modulo the total number of seats), and place each person from an already-fixed person; checking any 'not a neighbour of' constraint then pins down one unique arrangement.

Applying this to the clues given:

1. Fix C at position 0 as the reference seat.

2. G is second to the right of C, so G is at position 0 + 2 = 2.

3. B is fourth to the left of G, so B is at position 2 − 4 = −2 ≡ 7 (mod 9).

4. F is fourth to the right of C, so F is at position 0 + 4 = 4.

5. F is second to the left of K, so K is at position 4 + 2 = 6.

6. A is fourth to the right of K, so A is at position 6 + 4 = 10 ≡ 1 (mod 9).

7. Only positions 3, 5 and 8 remain for D, E and H. Testing E = 5 gives H = 5 + 3 = 8 (free); E = 3 would force H onto K's seat (6) and E = 8 would force H onto G's seat (2), so E = 5, H = 8, and D takes the last free seat, 3.

8. Check the neighbour condition: D (seat 3) sits between G (seat 2) and F (seat 4) — neither K (seat 6) nor B (seat 7) — so the constraint holds.

Final seating order:

Cross-check: K is at seat 6, so two seats to the right (6 + 2 = 8) lands on H — the same seat H already holds from the E-H clue, confirming the arrangement is consistent.

Therefore, H is second to the right of K.