Mohan walks 6 meters towards the south from his original position, takes a…

In direction-sense problems, when a person moves along two mutually perpendicular directions (here, south then west after a right turn), the straight-line distance from the starting point to the final point equals the hypotenuse of the right triangle formed by the two legs, given by the Pythagorean theorem: hypotenuse = √(leg12 + leg22).

1. Mohan walks 6 m south from the start (O) to a point (A).

2. Facing south, a right turn means he now faces west; he walks 8 m west from A to the end point (B).

3. South and west are perpendicular directions, so triangle OAB is right-angled at A, with legs OA = 6 m and AB = 8 m.

4. Distance OB = √(OA2 + AB2) = √(62 + 82) = √(36 + 64) = √100 = 10 m.

Cross-check: 6, 8, 10 is simply the 3-4-5 Pythagorean triple scaled by 2, which confirms the hypotenuse is 10 m without needing a full square-root computation.

So Mohan is 10 meters from his starting point.