Analogy: SLIPPER : 17 :: LOTUS : 7 :: PEACE : ?

Concept: Each letter of a word is converted to its position in the English alphabet (A = 1, B = 2, ..., Z = 26). The word is then split into two groups of letters — the first half (rounded up) and the remaining letters — and the code is the sum of the first group's positions minus the sum of the second group's positions.

Application:

1. SLIPPER has 7 letters: S = 19, L = 12, I = 9, P = 16, P = 16, E = 5, R = 18.

2. Split into a group of 4 and a group of 3: (S, L, I, P) sum to 19 + 12 + 9 + 16 = 56, and (P, E, R) sum to 16 + 5 + 18 = 39.

3. 56 − 39 = 17, which matches the given code for SLIPPER.

4. LOTUS has 5 letters: L = 12, O = 15, T = 20, U = 21, S = 19.

5. Split into a group of 3 and a group of 2: (L, O, T) sum to 12 + 15 + 20 = 47, and (U, S) sum to 21 + 19 = 40.

6. 47 − 40 = 7, which matches the given code for LOTUS and confirms the rule.

7. PEACE has 5 letters, so use the same 3-and-2 split as LOTUS: P = 16, E = 5, A = 1, C = 3, E = 5.

8. (P, E, A) sum to 16 + 5 + 1 = 22, and (C, E) sum to 3 + 5 = 8.

9. 22 − 8 = 14.

Cross-check: The two groups of any word must together add up to the sum of all its letters. For PEACE, every letter-position adds to 16 + 5 + 1 + 3 + 5 = 30, and indeed 22 + 8 = 30 — confirming the split was applied correctly. So PEACE codes to 14.