If thrice the first of three consecutive odd numbers is equal to 3 more than…

Three consecutive odd numbers can be represented algebraically as x, x + 2, and x + 4, where x is the first (smallest) and x + 4 is the last (largest) of the three. To find a specific term such as the '3rd largest', first solve for x from the given condition, then rank the three resulting numbers from largest to smallest.

Applying this to the given condition:

1. Let the three consecutive odd numbers be x, x + 2, and x + 4.

2. The condition states thrice the first number equals 3 more than twice the last number: 3x = 2(x + 4) + 3.

3. Expand the right-hand side: 3x = 2x + 8 + 3 = 2x + 11.

4. Solve for x: 3x - 2x = 11, so x = 11.

5. The three consecutive odd numbers are 11, 13, and 15.

6. Ranking them from largest to smallest: 15 is the 1st largest, 13 is the 2nd largest, and 11 is the 3rd largest.

Cross-check: 3 × 11 = 33, and 2 × 15 + 3 = 33 — both sides match, confirming x = 11 is correct.

Hence, the 3rd largest of the three odd numbers is 11.